Distance Calculator

Distance from Sayreville to Jackson

Distance between Sayreville and Jackson is 87 kilometers (54 miles).
Driving distance from Sayreville to Jackson is 103 kilometers (64 miles).

air 87 km
air 54 miles
car 103 km
car 64 miles

Distance Map Between Sayreville and Jackson

Sayreville, Trenton, United StatesJackson, Trenton, United States = 54 miles = 87 km.

How far is it between Sayreville and Jackson

Sayreville is located in United States with (40.4593,-74.361) coordinates and Jackson is located in United States with (39.7765,-74.8624) coordinates. The calculated flying distance from Sayreville to Jackson is equal to 54 miles which is equal to 87 km.

If you want to go by car, the driving distance between Sayreville and Jackson is 103.12 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 55 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 16 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sayreville 40.4593, -74.361 40° 27´ 33.3720'' N
74° 21´ 39.5280'' W
Jackson 39.7765, -74.8624 39° 46´ 35.4000'' N
74° 51´ 44.5680'' W

Estimated Travel Time Between Sayreville and Jackson

Average SpeedTravel Time
30 mph (48 km/h) 02 hours 08 minutes
40 mph (64 km/h) 01 hours 36 minutes
50 mph (80 km/h) 01 hours 17 minutes
60 mph (97 km/h) 01 hours 03 minutes
70 mph (112 km/h) 00 hours 55 minutes
75 mph (120 km/h) 00 hours 51 minutes
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