Distance Calculator

Distance from Sayreville to Hopatcong

Distance between Sayreville and Hopatcong is 58 kilometers (36 miles).
Driving distance from Sayreville to Hopatcong is 95 kilometers (59 miles).

air 58 km
air 36 miles
car 95 km
car 59 miles

Distance Map Between Sayreville and Hopatcong

Sayreville, Trenton, United StatesHopatcong, Trenton, United States = 36 miles = 58 km.

How far is it between Sayreville and Hopatcong

Sayreville is located in United States with (40.4593,-74.361) coordinates and Hopatcong is located in United States with (40.9329,-74.6593) coordinates. The calculated flying distance from Sayreville to Hopatcong is equal to 36 miles which is equal to 58 km.

If you want to go by car, the driving distance between Sayreville and Hopatcong is 94.92 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 50 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 37 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sayreville 40.4593, -74.361 40° 27´ 33.3720'' N
74° 21´ 39.5280'' W
Hopatcong 40.9329, -74.6593 40° 55´ 58.3680'' N
74° 39´ 33.5880'' W

Estimated Travel Time Between Sayreville and Hopatcong

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 58 minutes
40 mph (64 km/h) 01 hours 28 minutes
50 mph (80 km/h) 01 hours 11 minutes
60 mph (97 km/h) 00 hours 58 minutes
70 mph (112 km/h) 00 hours 50 minutes
75 mph (120 km/h) 00 hours 47 minutes
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