Distance Calculator

Distance from Sanford to Jacksonville

Distance between Sanford and Jacksonville is 178 kilometers (111 miles).
Driving distance from Sanford to Jacksonville is 207 kilometers (129 miles).

air 178 km
air 111 miles
car 207 km
car 129 miles

Distance Map Between Sanford and Jacksonville

Sanford, Raleigh, United StatesJacksonville, Raleigh, United States = 111 miles = 178 km.

How far is it between Sanford and Jacksonville

Sanford is located in United States with (35.4799,-79.1803) coordinates and Jacksonville is located in United States with (34.7541,-77.4302) coordinates. The calculated flying distance from Sanford to Jacksonville is equal to 111 miles which is equal to 178 km.

If you want to go by car, the driving distance between Sanford and Jacksonville is 207.03 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 50 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 29 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sanford 35.4799, -79.1803 35° 28´ 47.5680'' N
79° 10´ 49.0800'' W
Jacksonville 34.7541, -77.4302 34° 45´ 14.5800'' N
77° 25´ 48.8640'' W

Estimated Travel Time Between Sanford and Jacksonville

Average SpeedTravel Time
30 mph (48 km/h) 04 hours 18 minutes
40 mph (64 km/h) 03 hours 14 minutes
50 mph (80 km/h) 02 hours 35 minutes
60 mph (97 km/h) 02 hours 08 minutes
70 mph (112 km/h) 01 hours 50 minutes
75 mph (120 km/h) 01 hours 43 minutes
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