Distance from San Pablo to Okanagan
Distance between San Pablo and Okanagan is 1399 kilometers (869 miles).
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869 miles
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Distance Map Between San Pablo and Okanagan
San Pablo, Sacramento, United States ↔ Okanagan, Victoria, Canada = 869 miles = 1399 km.
How far is it between San Pablo and Okanagan
San Pablo is located in United States with (37.9622,-122.3455) coordinates and Okanagan is located in Canada with (50.3639,-119.35) coordinates. The calculated flying distance from San Pablo to Okanagan is equal to 869 miles which is equal to 1399 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| San Pablo | 37.9622, -122.3455 | 37° 57´ 43.7400'' N 122° 20´ 43.9080'' W |
| Okanagan | 50.3639, -119.35 | 50° 21´ 49.8960'' N 119° 20´ 59.8920'' W |
San Pablo, Sacramento, United States
Related Distances from San Pablo
| Cities | Distance |
|---|---|
| San Pablo 2 to Victoria | 1402 km |
| San Pablo 2 to Ontario | 673 km |
| San Pablo 2 to Saskatoon | 2653 km |
| San Pablo 2 to Ladner | 1482 km |
| San Pablo 2 to Vancouver | 1496 km |
Okanagan, Victoria, Canada
Related Distances to Okanagan
| Cities | Distance |
|---|---|
| Five Corners to Okanagan | 832 km |
| Thornton to Okanagan | 2171 km |
| Fairfield to Okanagan | 1798 km |
| Orangevale to Okanagan | 1803 km |
| Payson to Okanagan | 1679 km |