Distance from San Angelo to Portland
Distance between San Angelo and Portland is 499 kilometers (310 miles).
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310 miles
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Distance Map Between San Angelo and Portland
San Angelo, Austin, United States ↔ Portland, Austin, United States = 310 miles = 499 km.
How far is it between San Angelo and Portland
San Angelo is located in United States with (31.4638,-100.437) coordinates and Portland is located in United States with (27.8773,-97.3239) coordinates. The calculated flying distance from San Angelo to Portland is equal to 310 miles which is equal to 499 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| San Angelo | 31.4638, -100.437 | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
| Portland | 27.8773, -97.3239 | 27° 52´ 38.1000'' N 97° 19´ 25.9680'' W |
San Angelo, Austin, United States
Related Distances from San Angelo
| Cities | Distance |
|---|---|
| San Angelo to Garland | 442 km |
| San Angelo to Keller | 388 km |
| San Angelo to Denton | 420 km |
| San Angelo to Humble | 619 km |
| San Angelo to Midlothian | 407 km |
Portland, Austin, United States
Related Distances to Portland
| Cities | Distance |
|---|---|
| Fort Hood to Portland 3 | 431 km |
| Richardson to Portland 3 | 658 km |
| Lubbock to Portland 3 | 863 km |
| Texas City to Portland 3 | 339 km |
| Midland to Portland 3 | 766 km |