Distance from San Angelo to Dickinson

Distance between San Angelo and Dickinson is 562 kilometers (349 miles).
Driving distance from San Angelo to Dickinson is 638 kilometers (396 miles).

562 km

349 miles

638 km

396 miles

Distance Map Between San Angelo and Dickinson

San Angelo, Austin, United States ↔ Dickinson, Austin, United States = 349 miles = 562 km.

How far is it between San Angelo and Dickinson

San Angelo is located in United States with (31.4638,-100.437) coordinates and Dickinson is located in United States with (29.4608,-95.0513) coordinates. The calculated flying distance from San Angelo to Dickinson is equal to 349 miles which is equal to 562 km.

If you want to go by car, the driving distance between San Angelo and Dickinson is 637.75 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 05 hours 41 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 76 km.

City/Place	Latitude and Longitude	GPS Coordinates
San Angelo	31.4638, -100.437	31° 27´ 49.5720'' N 100° 26´ 13.3440'' W
Dickinson	29.4608, -95.0513	29° 27´ 38.8440'' N 95° 3´ 4.7520'' W

Estimated Travel Time Between San Angelo and Dickinson

Average Speed	Travel Time
30 mph (48 km/h)	13 hours 17 minutes
40 mph (64 km/h)	09 hours 57 minutes
50 mph (80 km/h)	07 hours 58 minutes
60 mph (97 km/h)	06 hours 34 minutes
70 mph (112 km/h)	05 hours 41 minutes
75 mph (120 km/h)	05 hours 18 minutes

San Angelo, Austin, United States

Related Distances from San Angelo

Cities	Distance
San Angelo to Deer Park	621 km
San Angelo to Friendswood	630 km
San Angelo to Kyle	358 km
San Angelo to University Park 2	423 km
San Angelo to Lufkin	612 km

Dickinson, Austin, United States

Related Distances to Dickinson

Cities	Distance
Minot to Dickinson 2	277 km
Temple to Dickinson	325 km
Plano to Dickinson	462 km
Odessa 2 to Dickinson	911 km
Houston to Dickinson	50 km