Distance Calculator

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Distance from San Angelo to Dickinson

Distance between San Angelo and Dickinson is 562 kilometers (349 miles).
Driving distance from San Angelo to Dickinson is 638 kilometers (396 miles).

air 562 km
air 349 miles
car 638 km
car 396 miles

Distance Map Between San Angelo and Dickinson

San Angelo, Austin, United StatesDickinson, Austin, United States = 349 miles = 562 km.

How far is it between San Angelo and Dickinson

San Angelo is located in United States with (31.4638,-100.437) coordinates and Dickinson is located in United States with (29.4608,-95.0513) coordinates. The calculated flying distance from San Angelo to Dickinson is equal to 349 miles which is equal to 562 km.

If you want to go by car, the driving distance between San Angelo and Dickinson is 637.75 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 05 hours 41 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 76 km.

City/PlaceLatitude and LongitudeGPS Coordinates
San Angelo 31.4638, -100.437 31° 27´ 49.5720'' N
100° 26´ 13.3440'' W
Dickinson 29.4608, -95.0513 29° 27´ 38.8440'' N
95° 3´ 4.7520'' W

Estimated Travel Time Between San Angelo and Dickinson

Average SpeedTravel Time
30 mph (48 km/h) 13 hours 17 minutes
40 mph (64 km/h) 09 hours 57 minutes
50 mph (80 km/h) 07 hours 58 minutes
60 mph (97 km/h) 06 hours 34 minutes
70 mph (112 km/h) 05 hours 41 minutes
75 mph (120 km/h) 05 hours 18 minutes

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