Distance from San Angelo to Deer Park

Distance between San Angelo and Deer Park is 545 kilometers (339 miles).
Driving distance from San Angelo to Deer Park is 621 kilometers (386 miles).

545 km

339 miles

621 km

386 miles

Distance Map Between San Angelo and Deer Park

San Angelo, Austin, United States ↔ Deer Park, Austin, United States = 339 miles = 545 km.

How far is it between San Angelo and Deer Park

San Angelo is located in United States with (31.4638,-100.437) coordinates and Deer Park is located in United States with (29.7052,-95.1238) coordinates. The calculated flying distance from San Angelo to Deer Park is equal to 339 miles which is equal to 545 km.

If you want to go by car, the driving distance between San Angelo and Deer Park is 621.16 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 05 hours 32 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 76 km.

City/Place	Latitude and Longitude	GPS Coordinates
San Angelo	31.4638, -100.437	31° 27´ 49.5720'' N 100° 26´ 13.3440'' W
Deer Park	29.7052, -95.1238	29° 42´ 18.8280'' N 95° 7´ 25.7520'' W

Estimated Travel Time Between San Angelo and Deer Park

Average Speed	Travel Time
30 mph (48 km/h)	12 hours 56 minutes
40 mph (64 km/h)	09 hours 42 minutes
50 mph (80 km/h)	07 hours 45 minutes
60 mph (97 km/h)	06 hours 24 minutes
70 mph (112 km/h)	05 hours 32 minutes
75 mph (120 km/h)	05 hours 10 minutes

San Angelo, Austin, United States

Related Distances from San Angelo

Cities	Distance
San Angelo to Farmers Branch	417 km
San Angelo to Cedar Park	315 km
San Angelo to Channelview	613 km
San Angelo to Del Rio	252 km
San Angelo to Mission Bend	570 km

Deer Park, Austin, United States

Related Distances to Deer Park

Cities	Distance
San Juan 4 to Deer Park	581 km
Holtsville to Deer Park 2	29 km
Nacogdoches to Deer Park	243 km
Depew to Deer Park 2	656 km
Roosevelt to Deer Park 2	29 km