Distance Calculator

Distance from Roosevelt to East Patchogue

Distance between Roosevelt and East Patchogue is 51 kilometers (32 miles).
Driving distance from Roosevelt to East Patchogue is 56 kilometers (35 miles).

air 51 km
air 32 miles
car 56 km
car 35 miles

Distance Map Between Roosevelt and East Patchogue

Roosevelt, Albany, United StatesEast Patchogue, Albany, United States = 32 miles = 51 km.

How far is it between Roosevelt and East Patchogue

Roosevelt is located in United States with (40.6787,-73.589) coordinates and East Patchogue is located in United States with (40.767,-72.9962) coordinates. The calculated flying distance from Roosevelt to East Patchogue is equal to 32 miles which is equal to 51 km.

If you want to go by car, the driving distance between Roosevelt and East Patchogue is 55.99 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 29 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 5 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Roosevelt 40.6787, -73.589 40° 40´ 43.3560'' N
73° 35´ 20.4720'' W
East Patchogue 40.767, -72.9962 40° 46´ 1.3440'' N
72° 59´ 46.3920'' W

Estimated Travel Time Between Roosevelt and East Patchogue

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 09 minutes
40 mph (64 km/h) 00 hours 52 minutes
50 mph (80 km/h) 00 hours 41 minutes
60 mph (97 km/h) 00 hours 34 minutes
70 mph (112 km/h) 00 hours 29 minutes
75 mph (120 km/h) 00 hours 27 minutes
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