Distance from Oxnard Shores to Huntington Park
Distance between Oxnard Shores and Huntington Park is 96 kilometers (60 miles).
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60 miles
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Distance Map Between Oxnard Shores and Huntington Park
Oxnard Shores, Sacramento, United States ↔ Huntington Park, Sacramento, United States = 60 miles = 96 km.
How far is it between Oxnard Shores and Huntington Park
Oxnard Shores is located in United States with (34.1908,-119.2415) coordinates and Huntington Park is located in United States with (33.9817,-118.2251) coordinates. The calculated flying distance from Oxnard Shores to Huntington Park is equal to 60 miles which is equal to 96 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Oxnard Shores | 34.1908, -119.2415 | 34° 11´ 27.0240'' N 119° 14´ 29.4000'' W |
| Huntington Park | 33.9817, -118.2251 | 33° 58´ 54.0480'' N 118° 13´ 30.2520'' W |
Oxnard Shores, Sacramento, United States
Related Distances from Oxnard Shores
| Cities | Distance |
|---|---|
| Oxnard Shores to Adelanto | 219 km |
| Oxnard Shores to Agoura | 56 km |
| Oxnard Shores to Agoura Hills | 53 km |
| Oxnard Shores to Alameda | 562 km |
| Oxnard Shores to Albany 5 | 579 km |
| Oxnard Shores to Alhambra | 120 km |
| Oxnard Shores to Aliso Viejo | 191 km |
| Oxnard Shores to Alum Rock | 504 km |
| Oxnard Shores to American Canyon | 617 km |
| Oxnard Shores to Anaheim | 154 km |
Huntington Park, Sacramento, United States