Distance from Oxnard Shores to Dixon
Distance between Oxnard Shores and Dixon is 527 kilometers (327 miles).
527 km
327 miles
0 km
0 miles
Distance Map Between Oxnard Shores and Dixon
Oxnard Shores, Sacramento, United States ↔ Dixon, Sacramento, United States = 327 miles = 527 km.
How far is it between Oxnard Shores and Dixon
Oxnard Shores is located in United States with (34.1908,-119.2415) coordinates and Dixon is located in United States with (38.4455,-121.8233) coordinates. The calculated flying distance from Oxnard Shores to Dixon is equal to 327 miles which is equal to 527 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Oxnard Shores | 34.1908, -119.2415 | 34° 11´ 27.0240'' N 119° 14´ 29.4000'' W |
| Dixon | 38.4455, -121.8233 | 38° 26´ 43.6560'' N 121° 49´ 23.8800'' W |
Oxnard Shores, Sacramento, United States
Related Distances from Oxnard Shores
| Cities | Distance |
|---|---|
| Oxnard Shores to Montebello | 129 km |
| Oxnard Shores to Antioch | 590 km |
| Oxnard Shores to Manhattan Beach | 122 km |
| Oxnard Shores to Hermosa Beach | 123 km |
| Oxnard Shores to Atwater | 472 km |
Dixon, Sacramento, United States
Related Distances to Dixon
| Cities | Distance |
|---|---|
| Tinley Park to Dixon 2 | 176 km |
| Elmhurst to Dixon 2 | 145 km |
| Rancho Cucamonga to Dixon | 688 km |
| Universal City to Dixon | 618 km |
| Sunnyvale to Dixon | 157 km |