Distance Calculator

Distance from Manhuacu to Sao Sebastiao do Paraiso

Distance between Manhuacu and Sao Sebastiao do Paraiso is 521 kilometers (324 miles).
Driving distance from Manhuacu to Sao Sebastiao do Paraiso is 678 kilometers (421 miles).

air 521 km
air 324 miles
car 678 km
car 421 miles

Distance Map Between Manhuacu and Sao Sebastiao do Paraiso

Manhuacu, Belo Horizonte, BrazilSao Sebastiao do Paraiso, Belo Horizonte, Brazil = 324 miles = 521 km.

How far is it between Manhuaçu and São Sebastião do Paraíso

Manhuacu is located in Brazil with (-20.2581,-42.0336) coordinates and Sao Sebastiao do Paraiso is located in Brazil with (-20.9169,-46.9914) coordinates. The calculated flying distance from Manhuacu to Sao Sebastiao do Paraiso is equal to 324 miles which is equal to 521 km.

If you want to go by car, the driving distance between Manhuacu and Sao Sebastiao do Paraiso is 677.87 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 06 hours 03 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 157 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Manhuacu -20.2581, -42.0336 20° 15´ 29.0160'' S
42° 2´ 0.9960'' W
Sao Sebastiao do Paraiso -20.9169, -46.9914 20° 55´ 0.9840'' S
46° 59´ 29.0040'' W

Estimated Travel Time Between Manhuaçu and São Sebastião do Paraíso

Average SpeedTravel Time
30 mph (48 km/h) 14 hours 07 minutes
40 mph (64 km/h) 10 hours 35 minutes
50 mph (80 km/h) 08 hours 28 minutes
60 mph (97 km/h) 06 hours 59 minutes
70 mph (112 km/h) 06 hours 03 minutes
75 mph (120 km/h) 05 hours 38 minutes
Please Share Your Comments