Distance from Lexington-Fayette to Havana
Distance between Lexington-Fayette and Havana is 1670 kilometers (1038 miles).
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Distance Map Between Lexington-Fayette and Havana
Lexington-Fayette, Frankfort, United States ↔ Havana, Cuba = 1038 miles = 1670 km.
How far is it between Lexington-Fayette and Havana
Lexington-Fayette is located in United States with (38.0498,-84.4586) coordinates and Havana is located in Cuba with (23.133,-82.383) coordinates. The calculated flying distance from Lexington-Fayette to Havana is equal to 1038 miles which is equal to 1670 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Lexington-Fayette | 38.0498, -84.4586 | 38° 2´ 59.2800'' N 84° 27´ 30.7800'' W |
| Havana | 23.133, -82.383 | 23° 7´ 58.8720'' N 82° 22´ 58.9440'' W |
Lexington-Fayette, Frankfort, United States
Related Distances from Lexington-Fayette
Havana, Cuba
Related Distances to Havana
| Cities | Distance |
|---|---|
| Camaguey to Havana | 549 km |
| Cienfuegos to Havana | 245 km |
| Guantanamo to Havana | 930 km |
| Artemisa to Havana | 67 km |
| Holguin to Havana | 752 km |
| Bayamo to Havana | 755 km |
| Ciego De Avila to Havana | 434 km |
| Gueines to Havana | 56 km |