Distance from Juneau to Lexington-Fayette
Distance between Juneau and Lexington-Fayette is 4198 kilometers (2609 miles).
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Distance Map Between Juneau and Lexington-Fayette
Juneau, United States ↔ Lexington-Fayette, Frankfort, United States = 2609 miles = 4198 km.
How far is it between Juneau and Lexington-Fayette
Juneau is located in United States with (58.3019,-134.4197) coordinates and Lexington-Fayette is located in United States with (38.0498,-84.4586) coordinates. The calculated flying distance from Juneau to Lexington-Fayette is equal to 2609 miles which is equal to 4198 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Juneau | 58.3019, -134.4197 | 58° 18´ 6.9840'' N 134° 25´ 10.9920'' W |
| Lexington-Fayette | 38.0498, -84.4586 | 38° 2´ 59.2800'' N 84° 27´ 30.7800'' W |
Juneau, United States
Related Distances from Juneau
| Cities | Distance |
|---|---|
| Juneau to Albany | 6173 km |
| Juneau to Annapolis | 6027 km |
| Juneau to Atlanta | 6015 km |
| Juneau to Augusta 3 | 6693 km |
| Juneau to Austin | 5750 km |
| Juneau to Baton Rouge | 6010 km |
| Juneau to Boston | 6447 km |
| Juneau to Carson City | 4079 km |
| Juneau to Charleston 2 | 5649 km |
| Juneau to Columbia | 6152 km |
Lexington-Fayette, Frankfort, United States