Distance from Jacksonville to Santa Cruz de El Seibo
Distance between Jacksonville and Santa Cruz de El Seibo is 1809 kilometers (1124 miles).
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Distance Map Between Jacksonville and Santa Cruz de El Seibo
Jacksonville, Tallahassee, United States ↔ Santa Cruz de El Seibo, Dominican Republic = 1124 miles = 1809 km.
How far is it between Jacksonville and Santa Cruz de El Seibo
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Santa Cruz de El Seibo is located in Dominican Republic with (18.7656,-69.0389) coordinates. The calculated flying distance from Jacksonville to Santa Cruz de El Seibo is equal to 1124 miles which is equal to 1809 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Santa Cruz de El Seibo | 18.7656, -69.0389 | 18° 45´ 56.1240'' N 69° 2´ 19.8960'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Allapattah | 551 km |
| Jacksonville to Altamonte Springs | 218 km |
| Jacksonville to Apopka | 224 km |
| Jacksonville to Aventura | 544 km |
| Jacksonville to Bartow | 331 km |
| Jacksonville to Bayonet Point | 311 km |
| Jacksonville to Bayshore Gardens | 423 km |
| Jacksonville to Belle Glade | 470 km |
| Jacksonville to Bellview | 578 km |
| Jacksonville to Bloomingdale | 349 km |
Santa Cruz de El Seibo, Dominican Republic