Distance from Jacksonville to San Cristobal
Distance between Jacksonville and San Cristobal is 1765 kilometers (1097 miles).
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1097 miles
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Distance Map Between Jacksonville and San Cristobal
Jacksonville, Tallahassee, United States ↔ San Cristobal, Dominican Republic = 1097 miles = 1765 km.
How far is it between Jacksonville and San Cristóbal
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and San Cristobal is located in Dominican Republic with (18.4167,-70.1) coordinates. The calculated flying distance from Jacksonville to San Cristobal is equal to 1097 miles which is equal to 1765 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| San Cristobal | 18.4167, -70.1 | 18° 25´ 0.0120'' N 70° 5´ 60.0000'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Altamonte Springs | 218 km |
| Jacksonville to Eustis | 201 km |
| Jacksonville to Deltona | 184 km |
| Jacksonville to Cutler | 583 km |
| Jacksonville to Citrus Park | 317 km |
San Cristobal, Dominican Republic
Related Distances to San Cristobal
| Cities | Distance |
|---|---|
| Azua to San Cristobal 2 | 89 km |
| Bani to San Cristobal 2 | 38 km |