Distance from Jacksonville to Saint John's
Distance between Jacksonville and Saint John's is 2488 kilometers (1546 miles).
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1546 miles
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Distance Map Between Jacksonville and Saint John's
Jacksonville, Tallahassee, United States ↔ Saint John's, Antigua and Barbuda = 1546 miles = 2488 km.
How far is it between Jacksonville and Saint John’s
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Saint John's is located in Antigua and Barbuda with (17.1172,-61.8457) coordinates. The calculated flying distance from Jacksonville to Saint John's is equal to 1546 miles which is equal to 2488 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Saint John's | 17.1172, -61.8457 | 17° 7´ 1.8120'' N 61° 50´ 44.6280'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Gainesville | 115 km |
| Jacksonville to East Lake | 330 km |
| Jacksonville to Ensley | 571 km |
| Jacksonville to Cutler | 583 km |
| Jacksonville to Boynton Beach | 475 km |