Distance from Jacksonville to Sagua de Tanamo
Distance between Jacksonville and Sagua de Tanamo is 1260 kilometers (783 miles).
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Distance Map Between Jacksonville and Sagua de Tanamo
Jacksonville, Tallahassee, United States ↔ Sagua de Tanamo, Holguin, Cuba = 783 miles = 1260 km.
How far is it between Jacksonville and Sagua de Tánamo
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Sagua de Tanamo is located in Cuba with (20.5819,-75.2414) coordinates. The calculated flying distance from Jacksonville to Sagua de Tanamo is equal to 783 miles which is equal to 1260 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Sagua de Tanamo | 20.5819, -75.2414 | 20° 34´ 54.9840'' N 75° 14´ 29.0040'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Coral Springs | 510 km |
| Jacksonville to Bartow | 331 km |
| Jacksonville to Country Club | 545 km |
| Jacksonville to Boston | 1840 km |
| Jacksonville to Hallandale Beach | 540 km |
Sagua de Tanamo, Holguin, Cuba
Related Distances to Sagua de Tanamo
| Cities | Distance |
|---|---|
| Moa to Sagua De Tanamo | 39 km |
| Cueto to Sagua De Tanamo | 86 km |
| Baguanos to Sagua De Tanamo | 122 km |
| Gibara to Sagua De Tanamo | 177 km |
| Banes to Sagua De Tanamo | 124 km |