Distance from Jacksonville to Lucaya
Distance between Jacksonville and Lucaya is 514 kilometers (319 miles).
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319 miles
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Distance Map Between Jacksonville and Lucaya
Jacksonville, Tallahassee, United States ↔ Lucaya, Freeport, Bahamas = 319 miles = 514 km.
How far is it between Jacksonville and Lucaya
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Lucaya is located in Bahamas with (26.5333,-78.6667) coordinates. The calculated flying distance from Jacksonville to Lucaya is equal to 319 miles which is equal to 514 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Lucaya | 26.5333, -78.6667 | 26° 31´ 59.9880'' N 78° 40´ 0.0120'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Allapattah | 551 km |
| Jacksonville to Altamonte Springs | 218 km |
| Jacksonville to Apopka | 224 km |
| Jacksonville to Aventura | 544 km |
| Jacksonville to Bartow | 331 km |
| Jacksonville to Bayonet Point | 311 km |
| Jacksonville to Bayshore Gardens | 423 km |
| Jacksonville to Belle Glade | 470 km |
| Jacksonville to Bellview | 578 km |
| Jacksonville to Bloomingdale | 349 km |