Distance from Jacksonville to Guaynabo
Distance between Jacksonville and Guaynabo is 2058 kilometers (1279 miles).
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Distance Map Between Jacksonville and Guaynabo
Jacksonville, Tallahassee, United States ↔ Guaynabo, Puerto Rico = 1279 miles = 2058 km.
How far is it between Jacksonville and Guaynabo
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Guaynabo is located in Puerto Rico with (18.3575,-66.111) coordinates. The calculated flying distance from Jacksonville to Guaynabo is equal to 1279 miles which is equal to 2058 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Guaynabo | 18.3575, -66.111 | 18° 21´ 26.8200'' N 66° 6´ 39.6000'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Ferry Pass | 566 km |
| Jacksonville to Fort Lauderdale | 525 km |
| Jacksonville to Glenvar Heights | 574 km |
| Jacksonville to Deerfield Beach | 501 km |
| Jacksonville to Belle Glade | 470 km |
Guaynabo, Puerto Rico
Related Distances to Guaynabo
| Cities | Distance |
|---|---|
| Ponce to Guaynabo | 113 km |
| Vega Baja to Guaynabo | 41 km |
| Mayagueez to Guaynabo | 182 km |
| Trujillo Alto to Guaynabo | 14 km |
| Adjuntas to Guaynabo | 129 km |