Distance from Jacksonville to Cayey
Distance between Jacksonville and Cayey is 2073 kilometers (1288 miles).
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1288 miles
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Distance Map Between Jacksonville and Cayey
Jacksonville, Tallahassee, United States ↔ Cayey, Puerto Rico = 1288 miles = 2073 km.
How far is it between Jacksonville and Cayey
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Cayey is located in Puerto Rico with (18.1119,-66.166) coordinates. The calculated flying distance from Jacksonville to Cayey is equal to 1288 miles which is equal to 2073 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Cayey | 18.1119, -66.166 | 18° 6´ 42.8760'' N 66° 9´ 57.6000'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Clermont | 267 km |
| Jacksonville to East Lake | 330 km |
| Jacksonville to Fort Walton Beach | 525 km |
| Jacksonville to Coconut Grove | 569 km |
| Jacksonville to Daytona Beach | 153 km |
Cayey, Puerto Rico
Related Distances to Cayey
| Cities | Distance |
|---|---|
| San Juan 2 to Cayey | 54 km |
| Manati to Cayey | 95 km |
| Guaynabo to Cayey | 44 km |
| Vega Baja to Cayey | 84 km |
| Fajardo to Cayey | 92 km |