Distance from Jacksonville to Arecibo
Distance between Jacksonville and Arecibo is 2003 kilometers (1245 miles).
2003 km
1245 miles
0 km
0 miles
Distance Map Between Jacksonville and Arecibo
Jacksonville, Tallahassee, United States ↔ Arecibo, Puerto Rico = 1245 miles = 2003 km.
How far is it between Jacksonville and Arecibo
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Arecibo is located in Puerto Rico with (18.4725,-66.7157) coordinates. The calculated flying distance from Jacksonville to Arecibo is equal to 1245 miles which is equal to 2003 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Arecibo | 18.4725, -66.7157 | 18° 28´ 20.8200'' N 66° 42´ 56.6280'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Clearwater | 356 km |
| Jacksonville to Boynton Beach | 475 km |
| Jacksonville to Golden Gate | 571 km |
| Jacksonville to East Lake | 330 km |
| Jacksonville to Cantonment | 587 km |
Arecibo, Puerto Rico
Related Distances to Arecibo
| Cities | Distance |
|---|---|
| Catano to Arecibo | 73 km |
| Yauco to Arecibo | 110 km |
| Vega Baja to Arecibo | 40 km |
| Guaynabo to Arecibo | 80 km |
| Cayey to Arecibo | 122 km |