Distance from Jacksonville to Clayton

Distance between Jacksonville and Clayton is 136 kilometers (85 miles).
Driving distance from Jacksonville to Clayton is 162 kilometers (101 miles).

136 km

85 miles

162 km

101 miles

Distance Map Between Jacksonville and Clayton

Jacksonville, Raleigh, United States ↔ Clayton, Raleigh, United States = 85 miles = 136 km.

How far is it between Jacksonville and Clayton

Jacksonville is located in United States with (34.7541,-77.4302) coordinates and Clayton is located in United States with (35.6507,-78.4564) coordinates. The calculated flying distance from Jacksonville to Clayton is equal to 85 miles which is equal to 136 km.

If you want to go by car, the driving distance between Jacksonville and Clayton is 162.14 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 26 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 26 km.

City/Place	Latitude and Longitude	GPS Coordinates
Jacksonville	34.7541, -77.4302	34° 45´ 14.5800'' N 77° 25´ 48.8640'' W
Clayton	35.6507, -78.4564	35° 39´ 2.5560'' N 78° 27´ 23.0040'' W

Estimated Travel Time Between Jacksonville and Clayton

Average Speed	Travel Time
30 mph (48 km/h)	03 hours 22 minutes
40 mph (64 km/h)	02 hours 32 minutes
50 mph (80 km/h)	02 hours 01 minutes
60 mph (97 km/h)	01 hours 40 minutes
70 mph (112 km/h)	01 hours 26 minutes
75 mph (120 km/h)	01 hours 21 minutes

Jacksonville, Raleigh, United States

Related Distances from Jacksonville

Cities	Distance
Jacksonville 2 to Goldsboro	106 km
Jacksonville 2 to Havelock	71 km
Jacksonville 2 to Boone	496 km
Jacksonville 2 to Carrboro	243 km
Jacksonville 2 to Greenville	117 km

Clayton, Raleigh, United States

Related Distances to Clayton

Cities	Distance
Hazelwood to Clayton 2	22 km
Kinston to Clayton	100 km
Lumberton to Clayton	139 km
Maryland Heights to Clayton 2	16 km
Fuquay Varina to Clayton	34 km