Distance from Greenburgh to East Patchogue
Distance between Greenburgh and East Patchogue is 77 kilometers (48 miles).
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48 miles
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Distance Map Between Greenburgh and East Patchogue
Greenburgh, Albany, United States ↔ East Patchogue, Albany, United States = 48 miles = 77 km.
How far is it between Greenburgh and East Patchogue
Greenburgh is located in United States with (41.0329,-73.8429) coordinates and East Patchogue is located in United States with (40.767,-72.9962) coordinates. The calculated flying distance from Greenburgh to East Patchogue is equal to 48 miles which is equal to 77 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Greenburgh | 41.0329, -73.8429 | 41° 1´ 58.3320'' N 73° 50´ 34.4760'' W |
| East Patchogue | 40.767, -72.9962 | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
Greenburgh, Albany, United States
Related Distances from Greenburgh
| Cities | Distance |
|---|---|
| Greenburgh to Amherst | 622 km |
| Greenburgh to Auburn 3 | 398 km |
| Greenburgh to Baldwin | 71 km |
| Greenburgh to Batavia 2 | 545 km |
| Greenburgh to Bay Shore | 102 km |
| Greenburgh to Beacon | 66 km |
| Greenburgh to Bensonhurst | 74 km |
| Greenburgh to Bethpage | 79 km |
| Greenburgh to Binghamton | 280 km |
| Greenburgh to Brentwood | 96 km |
East Patchogue, Albany, United States