Distance Calculator

Distance from Fuquay-Varina to Clayton

Distance between Fuquay-Varina and Clayton is 32 kilometers (20 miles).
Driving distance from Fuquay-Varina to Clayton is 34 kilometers (21 miles).

air 32 km
air 20 miles
car 34 km
car 21 miles

Distance Map Between Fuquay-Varina and Clayton

Fuquay-Varina, Raleigh, United StatesClayton, Raleigh, United States = 20 miles = 32 km.

How far is it between Fuquay-Varina and Clayton

Fuquay-Varina is located in United States with (35.5843,-78.8) coordinates and Clayton is located in United States with (35.6507,-78.4564) coordinates. The calculated flying distance from Fuquay-Varina to Clayton is equal to 20 miles which is equal to 32 km.

If you want to go by car, the driving distance between Fuquay-Varina and Clayton is 34.18 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 18 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 2 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Fuquay-Varina 35.5843, -78.8 35° 35´ 3.5520'' N
78° 48´ 0.0360'' W
Clayton 35.6507, -78.4564 35° 39´ 2.5560'' N
78° 27´ 23.0040'' W

Estimated Travel Time Between Fuquay-Varina and Clayton

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 42 minutes
40 mph (64 km/h) 00 hours 32 minutes
50 mph (80 km/h) 00 hours 25 minutes
60 mph (97 km/h) 00 hours 21 minutes
70 mph (112 km/h) 00 hours 18 minutes
75 mph (120 km/h) 00 hours 17 minutes
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