Distance from Florida Ridge to Havana
Distance between Florida Ridge and Havana is 534 kilometers (332 miles).
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332 miles
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Distance Map Between Florida Ridge and Havana
Florida Ridge, Tallahassee, United States ↔ Havana, Cuba = 332 miles = 534 km.
How far is it between Florida Ridge and Havana
Florida Ridge is located in United States with (27.5803,-80.3867) coordinates and Havana is located in Cuba with (23.133,-82.383) coordinates. The calculated flying distance from Florida Ridge to Havana is equal to 332 miles which is equal to 534 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Florida Ridge | 27.5803, -80.3867 | 27° 34´ 49.1160'' N 80° 23´ 12.1920'' W |
| Havana | 23.133, -82.383 | 23° 7´ 58.8720'' N 82° 22´ 58.9440'' W |
Florida Ridge, Tallahassee, United States
Related Distances from Florida Ridge
| Cities | Distance |
|---|---|
| Florida Ridge to Flagami | 229 km |
| Florida Ridge to Delray Beach | 147 km |
| Florida Ridge to Coconut Creek | 165 km |
| Florida Ridge to Altamonte Springs | 192 km |
| Florida Ridge to Deerfield Beach | 165 km |
Havana, Cuba
Related Distances to Havana
| Cities | Distance |
|---|---|
| Guantanamo to Havana | 930 km |
| Gueines to Havana | 56 km |
| Ciego De Avila to Havana | 434 km |
| Holguin to Havana | 752 km |
| Bayamo to Havana | 755 km |