Distance Calculator

Distance from Florida Ridge to Deerfield Beach

Distance between Florida Ridge and Deerfield Beach is 143 kilometers (89 miles).
Driving distance from Florida Ridge to Deerfield Beach is 165 kilometers (102 miles).

air 143 km
air 89 miles
car 165 km
car 102 miles

Distance Map Between Florida Ridge and Deerfield Beach

Florida Ridge, Tallahassee, United StatesDeerfield Beach, Tallahassee, United States = 89 miles = 143 km.

How far is it between Florida Ridge and Deerfield Beach

Florida Ridge is located in United States with (27.5803,-80.3867) coordinates and Deerfield Beach is located in United States with (26.3184,-80.0998) coordinates. The calculated flying distance from Florida Ridge to Deerfield Beach is equal to 89 miles which is equal to 143 km.

If you want to go by car, the driving distance between Florida Ridge and Deerfield Beach is 164.67 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 28 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 22 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Florida Ridge 27.5803, -80.3867 27° 34´ 49.1160'' N
80° 23´ 12.1920'' W
Deerfield Beach 26.3184, -80.0998 26° 19´ 6.2760'' N
80° 5´ 59.1720'' W

Estimated Travel Time Between Florida Ridge and Deerfield Beach

Average SpeedTravel Time
30 mph (48 km/h) 03 hours 25 minutes
40 mph (64 km/h) 02 hours 34 minutes
50 mph (80 km/h) 02 hours 03 minutes
60 mph (97 km/h) 01 hours 41 minutes
70 mph (112 km/h) 01 hours 28 minutes
75 mph (120 km/h) 01 hours 22 minutes
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