Distance from Farmington to Guadalupe
Distance between Farmington and Guadalupe is 1442 kilometers (896 miles).
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896 miles
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Distance Map Between Farmington and Guadalupe
Farmington, Santa Fe, United States ↔ Guadalupe, Monterrey, Mexico = 896 miles = 1442 km.
How far is it between Farmington and Guadalupe
Farmington is located in United States with (36.7281,-108.2187) coordinates and Guadalupe is located in Mexico with (25.6768,-100.2565) coordinates. The calculated flying distance from Farmington to Guadalupe is equal to 896 miles which is equal to 1442 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Farmington | 36.7281, -108.2187 | 36° 43´ 41.0160'' N 108° 13´ 7.2840'' W |
| Guadalupe | 25.6768, -100.2565 | 25° 40´ 36.4080'' N 100° 15´ 23.2560'' W |
Farmington, Santa Fe, United States
Related Distances from Farmington
| Cities | Distance |
|---|---|
| Farmington to Mexicali | 1019 km |
| Farmington to Tijuana | 1217 km |
| Farmington to Heroica Matamoros | 1884 km |
| Farmington to San Luis Potosi | 2127 km |
| Farmington to Ciudad Juarez | 723 km |
Guadalupe, Monterrey, Mexico
Related Distances to Guadalupe
| Cities | Distance |
|---|---|
| Erie 2 to Guadalupe | 1969 km |
| North Richland Hills to Guadalupe | 932 km |
| Lakeland to Guadalupe | 2356 km |
| Bayou Cane to Guadalupe | 1265 km |
| Tempe Junction to Guadalupe | 1864 km |