Distance from Boynton Beach to Havana
Distance between Boynton Beach and Havana is 444 kilometers (276 miles).
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Distance Map Between Boynton Beach and Havana
Boynton Beach, Tallahassee, United States ↔ Havana, Cuba = 276 miles = 444 km.
How far is it between Boynton Beach and Havana
Boynton Beach is located in United States with (26.5254,-80.0664) coordinates and Havana is located in Cuba with (23.133,-82.383) coordinates. The calculated flying distance from Boynton Beach to Havana is equal to 276 miles which is equal to 444 km.
City/Place | Latitude and Longitude | GPS Coordinates |
---|---|---|
Boynton Beach | 26.5254, -80.0664 | 26° 31´ 31.2600'' N 80° 3´ 59.1480'' W |
Havana | 23.133, -82.383 | 23° 7´ 58.8720'' N 82° 22´ 58.9440'' W |
Boynton Beach, Tallahassee, United States
Related Distances from Boynton Beach
Cities | Distance |
---|---|
Boynton Beach to Bartow | 276 km |
Boynton Beach to Bloomingdale | 322 km |
Boynton Beach to Aventura | 71 km |
Boynton Beach to Bellview | 1002 km |
Boynton Beach to Altamonte Springs | 308 km |
Havana, Cuba
Related Distances to Havana
Cities | Distance |
---|---|
Holguin to Havana | 752 km |
Artemisa to Havana | 67 km |
Bayamo to Havana | 755 km |
Gueines to Havana | 56 km |
Cienfuegos to Havana | 245 km |