Distance Calculator

Distance from Bogdanovich to Serov

Distance between Bogdanovich and Serov is 325 kilometers (202 miles).
Driving distance from Bogdanovich to Serov is 447 kilometers (278 miles).

air 325 km
air 202 miles
car 447 km
car 278 miles

Distance Map Between Bogdanovich and Serov

Bogdanovich, Yekaterinburg, RussiaSerov, Yekaterinburg, Russia = 202 miles = 325 km.

How far is it between Bogdanovich and Serov

Bogdanovich is located in Russia with (56.7803,62.0494) coordinates and Serov is located in Russia with (59.6033,60.5787) coordinates. The calculated flying distance from Bogdanovich to Serov is equal to 202 miles which is equal to 325 km.

If you want to go by car, the driving distance between Bogdanovich and Serov is 446.65 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 03 hours 59 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 122 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Bogdanovich 56.7803, 62.0494 56° 46´ 49.0080'' N
62° 2´ 57.9840'' E
Serov 59.6033, 60.5787 59° 36´ 12.0240'' N
60° 34´ 43.3200'' E

Estimated Travel Time Between Bogdanovich and Serov

Average SpeedTravel Time
30 mph (48 km/h) 09 hours 18 minutes
40 mph (64 km/h) 06 hours 58 minutes
50 mph (80 km/h) 05 hours 34 minutes
60 mph (97 km/h) 04 hours 36 minutes
70 mph (112 km/h) 03 hours 59 minutes
75 mph (120 km/h) 03 hours 43 minutes
Serov, Yekaterinburg, Russia

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