Distance from Albany to Lexington-Fayette
Distance between Albany and Lexington-Fayette is 1040 kilometers (646 miles).
1040 km
646 miles
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Distance Map Between Albany and Lexington-Fayette
Albany, United States ↔ Lexington-Fayette, Frankfort, United States = 646 miles = 1040 km.
How far is it between Albany and Lexington-Fayette
Albany is located in United States with (42.6526,-73.7562) coordinates and Lexington-Fayette is located in United States with (38.0498,-84.4586) coordinates. The calculated flying distance from Albany to Lexington-Fayette is equal to 646 miles which is equal to 1040 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Albany | 42.6526, -73.7562 | 42° 39´ 9.2880'' N 73° 45´ 22.4280'' W |
| Lexington-Fayette | 38.0498, -84.4586 | 38° 2´ 59.2800'' N 84° 27´ 30.7800'' W |
Albany, United States
Related Distances from Albany
| Cities | Distance |
|---|---|
| Albany to Annapolis | 569 km |
| Albany to Atlanta | 1616 km |
| Albany to Augusta 3 | 519 km |
| Albany to Austin | 2970 km |
| Albany to Baton Rouge | 2386 km |
| Albany to Binghamton | 225 km |
| Albany to Boston | 273 km |
| Albany to Buffalo | 465 km |
| Albany to Charleston 2 | 1053 km |
| Albany to Columbia | 1382 km |
Lexington-Fayette, Frankfort, United States